X^2-2x+10=2

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Solution for X^2-2x+10=2 equation: 



X^2-2X+10=2

We move all terms to the left:

X^2-2X+10-(2)=0

We add all the numbers together, and all the variables

X^2-2X+8=0

a = 1; b = -2; c = +8;
Δ = b2-4ac
Δ = -22-4·1·8
Δ = -28
Delta is less than zero, so there is no solution for the equation

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